Search any question & find its solution
Question:
Answered & Verified by Expert
The ionisation energy of $\mathrm{Li}^{2+}$ is equal to
Options:
Solution:
2561 Upvotes
Verified Answer
The correct answer is:
$9 h c R$
Ionization energy $=R c h Z^{2}$
$$
Z=3 \text { for } \mathrm{Li}^{2+}
$$
$\therefore$ Ionization energy $=(3)^{2} R c h=9 R c h$
$$
Z=3 \text { for } \mathrm{Li}^{2+}
$$
$\therefore$ Ionization energy $=(3)^{2} R c h=9 R c h$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.