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The ionization constant of propanoic acid is 1.32 × 10-5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?
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The correct answer is:
α = 0.0016, pH = 3.10, α' = 0.00013
Correct Option is : (A)
α = 0.0016, pH = 3.10, α' = 0.00013
α = 0.0016, pH = 3.10, α' = 0.00013
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