The ionization energy of gaseous Na atoms is 495 . 5 kJ mol - 1 . The lowest possible frequency of light that ionizes a sodium atom is ( h = 6.626 × 1 0 - 3 4 Js , N A = 6.022 × 1 0 2 3 mol -1 )

Question

The ionization energy of gaseous Na atoms is 495 . 5 kJ mol - 1 . The lowest possible frequency of light that ionizes a sodium atom is ( h = 6.626 × 1 0 - 3 4 Js , N A = 6.022 × 1 0 2 3 mol -1 ), 1.24 × 1 0 1 5 s -1, 7.50 × 1 0 4 s -1, 4.76 × 1 0 1 4 s -1, 3.15 × 1 0 1 5 s -1

MARKS App · Accepted Answer

One photon ionises one Na - atom by elastic collision. NA hv photon × 10 – 3 ( KJ mole – 1 ) 6 · 022 × 10 23 × 6 · 626 × 10 - 34 × υ photon × 10 - 3 = 495 · 5 υ photon = 495 · 5 6 · 022 × 6 · 626 × 10 - 14 = 12 . 41 × 10 14 = 1 · 2 4 1 × 1 0 1 5 sec - 1

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