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Question: Answered & Verified by Expert
The joint equation of lines passing through the origin and trisecting the first quadrant is ________
MathematicsPair of LinesMHT CETMHT CET 2016
Options:
  • A x2+3xy-y2=0
  • B x2-3xy-y2=0
  • C 3x2-4xy+3y2=0
  • D 3x2-y2=0
Solution:
2326 Upvotes Verified Answer
The correct answer is: 3x2-4xy+3y2=0

As given, both line passes through 0, 0 and θ1=π6,  θ2=π3
  Equation of first line is.
y-0=tanπ6x-0
 y=13x
 x-3y=0 ...... (i)
Equation of second line is
y-0=tanπ3(x-0)
 y=3 x
 3 x-y=0 ...... (ii)
Hence, joint equation of these line is
x-3y3x-y=0
  3x2-xy-3xy+3y2=0
   3x2+3y2-4xy=0

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