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Question: Answered & Verified by Expert
The $K_{\mathrm{H}}$ value ( $\mathrm{K}$ bar) of argon (I), carbondioxide (II), formaldehyde (III) and methane (IV) are respectively 40.3, 167, $1.83 \times 0^{-5}$ and $0.413$ at $298 \mathrm{~K}$. The increasing order of solubility of gas in liquid is
ChemistrySolutionsKCETKCET 2021
Options:
  • A I $ < $ II $ < $ IV $ < $ III
  • B III $ < $ IV $ < $ II $ < $ I
  • C $\mathrm{I} < \mathrm{III} < \mathrm{II} < \mathrm{IV}$
  • D I $ < \mathrm{IV} < \mathrm{II} < \mathrm{III}$
Solution:
1209 Upvotes Verified Answer
The correct answer is: I $ < $ II $ < $ IV $ < $ III
Higher is the $K_{\mathrm{H}}$ value, less is the solubility of the gas.



Thus, the increasing order of solubility of gas in liquid is I < II < IV < III.

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