The K ⁡ α X -ray emission line of tungsten occurs at λ = 0 . 0 2 1 nm . The energy difference between K and L levels in this atom is about

Question

The K ⁡ α X -ray emission line of tungsten occurs at λ = 0 . 0 2 1 nm . The energy difference between K and L levels in this atom is about, 0 . 5 1 MeV, 1. 2 MeV, 5 9 keV, 1 3 . 6 eV

MARKS App · Accepted Answer

λ k ⁡ α = 0 . 0 2 1 nm = 0 . 2 1 A ∘ Since, λ k ⁡ α corresponds to the transition of an electron from L -shell to K -shell, therefore E ⁡ L ⁡ - E ⁡ K ⁡ = in eV = 1 2 3 7 5 λ in A ∘ = 1 2 3 7 5 0 .21 ≈ 5 8 9 28 eV or Δ E = 5 9 keV

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