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The kinetic energy of the electron in an orbit of radius $r$ in hydrogen atom is proportional to ( $e=$ electronic charge $)$
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The correct answer is:
$\frac{e^2}{2 r}$
The potential energy of the electron in the nth orbit of radius $r$ in Hatom, $U=\frac{e^2}{r}$ (in CGS)
$\because$ K.E. $=\frac{1}{2} \mid$ P.E. $\mid \Rightarrow K=\frac{e^2}{2 r}$
$\because$ K.E. $=\frac{1}{2} \mid$ P.E. $\mid \Rightarrow K=\frac{e^2}{2 r}$
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