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The last digit of number $7^{886}$ is
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The correct answer is:
9
Since, $\quad 7^{1}=7$
$7^{2}=49,7^{3}=343,7^{4}=2401$
$\therefore \quad 7^{886}=\left(7^{4}\right)^{221} 7^{2}$
$\therefore$ The last digit number $7^{886}$ is 9 .
$7^{2}=49,7^{3}=343,7^{4}=2401$
$\therefore \quad 7^{886}=\left(7^{4}\right)^{221} 7^{2}$
$\therefore$ The last digit number $7^{886}$ is 9 .
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