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Question: Answered & Verified by Expert
The last element of the $p$-block in 6th period is represented by the outer most electronic configuration.
ChemistryStructure of AtomKCETKCET 2020
Options:
  • A $7 s^{2}, 7 p^{6}$,
  • B $5 f^{14} 6 d{ }^{10} 7 s^{2}, 7 p^{5}$
  • C $4 f^{14}, 5 d^{10}, 6 s^{2}, 6 p^{4}$
  • D $4 f,{ }^{14} 5 d,^{10} 6 s^{2}, 6 p^{6}$
Solution:
2745 Upvotes Verified Answer
The correct answer is: $4 f,{ }^{14} 5 d,^{10} 6 s^{2}, 6 p^{6}$
The last element in the sixth period will be noble gas Rn with atomic number 86 and electronic configuration $4 f^{14}, 5 d^{10}, 6 s^{2}, 6 p^{6}$.

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