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The length of a pendulum is measured as $1.01 \mathrm{~m}$ and time for 30 oscillations is measured as one minute $3 \mathrm{~s}$. Error length is $0.01 \mathrm{~m}$ and error in time is $3 \mathrm{~s}$. The percentage error in the measurement of acceleration due to gravity is
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Verified Answer
The correct answer is:
$10$
$\frac{\Delta g}{g}=\frac{\Delta l}{l}+\frac{2 \Delta T}{T}$
We get,
$\frac{\Delta g}{g} \%=10 \%$
We get,
$\frac{\Delta g}{g} \%=10 \%$
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