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The length of latus rectum of the ellipse $4 x^{2}+9 y^{2}=36$ is
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$\frac{8}{3}$
$4 \mathrm{x}^{2}+9 \mathrm{y}^{2}=36$
$\frac{x^{2}}{3^{2}}+\frac{y^{2}}{2^{2}}=1$
Length of latus rectum $=2 \times \frac{2^{2}}{3}=\frac{8}{3}$
$\frac{x^{2}}{3^{2}}+\frac{y^{2}}{2^{2}}=1$
Length of latus rectum $=2 \times \frac{2^{2}}{3}=\frac{8}{3}$
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