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The length of the latus rectum of the ellipse \(16 x^2+25 y^2=400\) is
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Verified Answer
The correct answer is:
\(32 / 5\) unit
Hints : Length of latus rectum \(=2 \frac{b^2}{a}=\frac{2 \times 16}{5}=\frac{32}{5}\)
\(\begin{aligned}
& 16 x^2+25 y^2=400 \\
& \frac{x^2}{25}+\frac{y^2}{16}=1 \\
& a^2=25 ; b^2=16
\end{aligned}\)
\(\begin{aligned}
& 16 x^2+25 y^2=400 \\
& \frac{x^2}{25}+\frac{y^2}{16}=1 \\
& a^2=25 ; b^2=16
\end{aligned}\)
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