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The length of the perpendicular from the origin to the plane $\bar{r}$. $(3 \hat{i}-4 \hat{j}+12 \hat{k})=8$ is
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$\frac{8}{13}$
The required length of perpendicular $=\frac{8}{\sqrt{3^2+(-4)^2+12^2}}=\frac{8}{13}$
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