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The light rays having photons of energy 1.8 eV are falling on a metal surface having a work function $1 \cdot 2 \mathrm{eV}$. What is the stopping potential to be applied to stop the emitting electrons ?
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0.6 eV
Maximum kinetic energy of photoelectron
$\begin{aligned} & (\mathrm{KE})_{\max }=E-\phi \\ & =1.8-1.2 \\ & =0.6 \mathrm{eV} \\ & \text { i.e., } \quad e V_0=(\mathrm{KE})_{\max } \\ & \text { or } \quad e V_0=0.6 \mathrm{eV} \\ & \end{aligned}$
$\therefore$ Stopping potential $V_0=0.6 \mathrm{eV}$.
$\begin{aligned} & (\mathrm{KE})_{\max }=E-\phi \\ & =1.8-1.2 \\ & =0.6 \mathrm{eV} \\ & \text { i.e., } \quad e V_0=(\mathrm{KE})_{\max } \\ & \text { or } \quad e V_0=0.6 \mathrm{eV} \\ & \end{aligned}$
$\therefore$ Stopping potential $V_0=0.6 \mathrm{eV}$.
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