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The load resistance and the base-emitter voltage of a transistor in CE configuration are $5 \mathrm{k} \Omega$ and $0.02 \mathrm{~V}$ respectively. If the collector current is $2 \mathrm{~mA}$, then its voltage gain is
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$500$
$\mathrm{I}_{\mathrm{C}}=2 \times 10^{-3} \mathrm{~A}$
Voltage gain, $A_v=\frac{V_{C E}}{V_{B E}}=\frac{I_c R_c}{V_{B E}}$ $=\frac{2 \times 10^{-3} \times 5 \times 10^3}{.02}=500$
Voltage gain, $A_v=\frac{V_{C E}}{V_{B E}}=\frac{I_c R_c}{V_{B E}}$ $=\frac{2 \times 10^{-3} \times 5 \times 10^3}{.02}=500$
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