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The locus of the mid-points of chords of the circle $x^{2}+y^{2}=1$, which subtends a right angle at the origin, is
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Verified Answer
The correct answer is:
$x^{2}+y^{2}=\frac{1}{2}$
Let $(h, k)$ be the coordinates of the mid-point of a chord which subtends a right angle at the origin. Then, equation of the chord is
$$
\begin{array}{l}
\quad h x+h y-1=h^{2}+k^{2}-1 \quad[u \operatorname{sing} T=S] \\
\Rightarrow \quad h x+k y=h^{2}+k^{2}
\end{array}
$$
The combined equation of the pair of lines joining the origin to the points of intersection of $x^{2}+y^{2}=1$ and $h x+k y=h^{2}+k^{2}$ is
$$
x^{2}+y^{2}-1\left(\frac{h x+h y}{h^{2}+k^{2}}\right)^{2}=0
$$
Lines given by the above equation are at right angle. Therefore, coefficient of $x^{2}+$ coefficient of $y^{2}=0$
ie. $\quad h^{2}+k^{2}=\frac{1}{2}$
$\therefore x^{2}+y^{2}=\frac{1}{2}$
$$
\begin{array}{l}
\quad h x+h y-1=h^{2}+k^{2}-1 \quad[u \operatorname{sing} T=S] \\
\Rightarrow \quad h x+k y=h^{2}+k^{2}
\end{array}
$$
The combined equation of the pair of lines joining the origin to the points of intersection of $x^{2}+y^{2}=1$ and $h x+k y=h^{2}+k^{2}$ is
$$
x^{2}+y^{2}-1\left(\frac{h x+h y}{h^{2}+k^{2}}\right)^{2}=0
$$
Lines given by the above equation are at right angle. Therefore, coefficient of $x^{2}+$ coefficient of $y^{2}=0$
ie. $\quad h^{2}+k^{2}=\frac{1}{2}$
$\therefore x^{2}+y^{2}=\frac{1}{2}$
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