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Question: Answered & Verified by Expert
The locus of the point of intersection of the tangents at the extremities of a chord of the circle x2+y2=r2 which touches the circle x2+y2+2rx=0 is
MathematicsCircleJEE Main
Options:
  • A y2=2rx-r2
  • B y2=-2rx+r2
  • C y2=2rx+r2
  • D y2=-2rx-r2
Solution:
2462 Upvotes Verified Answer
The correct answer is: y2=2rx+r2
Let, point of intersection of the tangents is h,k.

Chord of contact through h,k for the circle x2+y2=r2 is

hx+ky-r2=0 which touches the circle x2+y2+2rx=0

 The distance of hx+ky-r2=0 from the centre -r,0 of circle x2+y2+2rx=0

is equal to the radius r of the circle x2+y2+2rx=0

h-r+k0-r2h2+k2=r

h+r=h2+k2

x2+2rx+r2=x2+y2y2=2rx+r2 is the required locus

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