The magnetic field associated with a light wave is given, at the origin, by B = B 0 sin ⁡ 3.14 × 10 7 c t + sin ⁡ 6.28 × 10 7 c t . If this light falls on a silver plate having a work function of 4 .7 eV , what will be the maximum kinetic energy of the photoelectrons? ( c = 3 × 10 8 m s − 1 , h = 6 .6 × 10 − 34 J s )

Question

The magnetic field associated with a light wave is given, at the origin, by B = B 0 sin ⁡ 3.14 × 10 7 c t + sin ⁡ 6.28 × 10 7 c t . If this light falls on a silver plate having a work function of 4 .7 eV , what will be the maximum kinetic energy of the photoelectrons? ( c = 3 × 10 8 m s − 1 , h = 6 .6 × 10 − 34 J s ), 6 .82 eV, 7 .72 eV, 12 .5 eV, 8 .52 eV

MARKS App · Accepted Answer

B = B 0 sin ⁡ 3.14 × 10 7 c t + sin ⁡ 6.28 × 10 7 c t Maximum K E will associate with the maximum frequency f max ⁡ = 6.28 × 10 7 c 2 π = 10 7 × 3 × 10 8 Hz = 3 × 10 15 Hz K E m a x = h f m a x - ϕ = 6 .63 × 10 - 34 × 3 × 10 15 1 .6 × 10 - 19 - 4 .7 eV = 7 .72 eV

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