The magnetic field B due to a current-carrying circular loop of the radius 12 cm at its centre is 0.5 × 10 – 4 T . The magnetic field due to this loop at a point on the axis at a distance of 5 cm from the centre -

Question

The magnetic field B due to a current-carrying circular loop of the radius 12 cm at its centre is 0.5 × 10 – 4 T . The magnetic field due to this loop at a point on the axis at a distance of 5 cm from the centre -, 3.9 × 10 – 5 T, 5.2 × 10 – 5 T, 2.1 × 10 – 5 T, 9 × 10 – 5 T

MARKS App · Accepted Answer

B 0 = μ 0 I 2 a At axial point B = μ 0 I a 2 2 ( a 2 + x 2 ) 3 / 2 B B 0 = a 3 ( a 2 + x 2 ) 3 / 2 ⇒ B = B 0 a 3 ( a 2 + x 2 ) 3 / 2 = 0.5 × 10 – 4 × ( 12 c m ) 3 ( 144 c m 2 + 25 c m 2 ) 3 / 2 = 3.9 × 10 – 5 T .

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