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The magnitude and direction of the current in the circuit shown will be
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Verified Answer
The correct answer is:
$1 \mathrm{~A}$ from a to b through $\mathrm{e}$
The current in the circuit will be clockwise Since $\mathrm{E}_{1}(10 \mathrm{~V})>\mathrm{E}_{2}(4 \mathrm{~V})$
Applying Kirchhoff's junction rule
$$
\begin{array}{l}
-1 \times i-10-4 \times-2 \times i-3 i=0 \\
i=1 \mathrm{~A} \quad \text { (a to b via e) }
\end{array}
$$
Current $\mathrm{I}=\frac{V}{R}=\frac{10-4}{6}=1 \mathrm{~A}$
Applying Kirchhoff's junction rule
$$
\begin{array}{l}
-1 \times i-10-4 \times-2 \times i-3 i=0 \\
i=1 \mathrm{~A} \quad \text { (a to b via e) }
\end{array}
$$
Current $\mathrm{I}=\frac{V}{R}=\frac{10-4}{6}=1 \mathrm{~A}$
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