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Question: Answered & Verified by Expert
The magnitude of total energy and angular momentum of an electron in the $\mathrm{n}^{\mathrm{th}}$ orbit of a Bohr atom is denoted by $E_{n}$ and $L_{n}$ respectively. Then
PhysicsAtomic PhysicsMHT CETMHT CET 2020 (15 Oct Shift 2)
Options:
  • A $\mathrm{E}_{\mathrm{n}} \propto \mathrm{L}_{\mathrm{n}}$
  • B $\mathrm{E}_{\mathrm{n}} \propto \mathrm{L}_{\mathrm{n}}^{3}$
  • C $\mathrm{E}_{\mathrm{n}} \propto \frac{1}{\mathrm{~L}_{\mathrm{n}}^{2}}$
  • D $\mathrm{E}_{\mathrm{n}} \propto \frac{1}{\mathrm{~L}_{\mathrm{n}}}$
Solution:
1994 Upvotes Verified Answer
The correct answer is: $\mathrm{E}_{\mathrm{n}} \propto \frac{1}{\mathrm{~L}_{\mathrm{n}}^{2}}$
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