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The main reduction product of the following compound with $\mathrm{NaBH}_4$ in methanol is :
Options:
- A
- B
- C
- D
Solution:
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Verified Answer
The correct answer is:
Sodium borohydride reduces ketonic group to alcohol, but not the amide group and $\mathrm{C}=\mathrm{C}$ double bond.
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