The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double - slit experiment is

Question

The maximum number of possible interference maxima for slit-separation equal to twice the wavelength in Young's double - slit experiment is, infinite, five, three, zero

MARKS App · Accepted Answer

For maxima, d s i n θ = n λ ⇒ 2 λ s i n θ = n λ ⇒ 2 s i n θ = n ∴ s i n θ = n 2 ∵ s i n θ 1 ⇒ n 2 1 ⇒ n 2 n = 0,1 maximum number of possible maxima = 3 n = 0 , ± 1

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