The maximum value of f ( x ) = sin ( x ) in the interval - π 2 , π 2 is

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Question: Answered & Verified by Expert

The maximum value of

f (x) = \sin (x)

in the interval

[\frac{- π}{2}, \frac{π}{2}]

is

MathematicsTrigonometric Ratios & IdentitiesAP EAMCETAP EAMCET 2021 (19 Aug Shift 2)

Options:

A $- 1$
B $- 1$
C $1$
D $\sqrt{2}$

Solution:

2061 Upvotes Verified Answer

The correct answer is:

1

Drawing the curve of

$f (x) = \sin x$

We can see that at $x = \frac{π}{2}$ , we get maxima, which is the value $f (x) = 1 .$

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