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Question: Answered & Verified by Expert
The maximum value of $z=7 x+8 y$ subject to the constraints $x+y \leq 20, y \geq 5, x \leq 10, x \geq 0, y \geq 0$ is
MathematicsLinear ProgrammingMHT CETMHT CET 2023 (12 May Shift 2)
Options:
  • A $150$
  • B $160$
  • C $110$
  • D $180$
Solution:
2584 Upvotes Verified Answer
The correct answer is: $160$


Feasible region lies on the origin side of lines $x+y=20, x=10$ and on non-origin side of $y=5$.
$\therefore \quad$ Corner points of the feasible region are $\mathrm{A}(0,5), \mathrm{B}(10,5), \mathrm{C}(10,10)$ and $\mathrm{D}(0,20)$
$\mathrm{z}$ at $\mathrm{A}(0,5)=40$
$\mathrm{z}$ at $\mathrm{B}(10,5)=110$
$\mathrm{z}$ at $\mathrm{C}(10,10)=150$
$\mathrm{z}$ at $\mathrm{D}(0,20)=160$
$\therefore \quad$ Maximum value of $\mathrm{z}$ is 160 .

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