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Question: Answered & Verified by Expert

The molar conductivity of 0.007 M acetic acid is 20 S cm2 mol-1. What is the dissociation constant of acetic acid? Choose the correct option.

λH+=350 S cm2 mol-1λCH3COO-=50 S cm2 mol-1

ChemistryElectrochemistryNEETNEET 2021
Options:
  • A 1.75×10-4 mol L-1
  • B 2.50×10-4 mol L-1
  • C 1.75×10-5 mol L-1
  • D 2.50×10-5 mol L-1
Solution:
1024 Upvotes Verified Answer
The correct answer is: 1.75×10-5 mol L-1

λCH3COOH=λCH3COO-+λH+

λCH3COO-=350+50=400 S cm2 mol-1

λCH3COOH=20Scm2 mol-1 given

α=λCH3COOHλCH3COOH=20400=5×10-2

Ka=2=0.007×5×10-22=1.75×10-5 molL-1

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