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The molar specific heat at constant pressure of an ideal gas is (7/2) $R$. The ratio of specific heat at constant pressure to that at constant volume is:
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Verified Answer
The correct answer is:
$7 / 5$
Molar specific heat at constant pressure
$$
C_P=\frac{7}{2} R
$$
We know that $C_P-C_V=R$
$$
\Rightarrow \quad \begin{aligned}
C_V & =C_P-R \\
& =\frac{7}{2} R-R=\frac{5}{2} R
\end{aligned}
$$
from (i) and (ii),
$$
\therefore \quad \frac{C_P}{C_V}=\frac{7}{5} .
$$
$$
C_P=\frac{7}{2} R
$$
We know that $C_P-C_V=R$
$$
\Rightarrow \quad \begin{aligned}
C_V & =C_P-R \\
& =\frac{7}{2} R-R=\frac{5}{2} R
\end{aligned}
$$
from (i) and (ii),
$$
\therefore \quad \frac{C_P}{C_V}=\frac{7}{5} .
$$
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