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The negation of the logical statement $(\mathrm{p} \vee \sim \mathrm{q}) \rightarrow(\mathrm{p} \wedge \sim \mathrm{q})$ is
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The correct answer is:
$(p \vee \sim q) \wedge(\sim p \vee q)$
$\sim[p \vee \sim q \rightarrow(p \wedge \sim q)]$
$\equiv \sim \sim(p \vee \sim q) \vee(p \wedge \sim q)]$
$\equiv(p \vee \sim q) \wedge \sim(p \wedge \sim q)$
$\equiv(p \vee \sim q) \wedge(\sim p \vee q)$
$\equiv \sim \sim(p \vee \sim q) \vee(p \wedge \sim q)]$
$\equiv(p \vee \sim q) \wedge \sim(p \wedge \sim q)$
$\equiv(p \vee \sim q) \wedge(\sim p \vee q)$
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