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The negation of the statement pattern $p v(q \rightarrow \sim r)$ is
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The correct answer is:
$\sim p \wedge(q \wedge r)$
$\begin{aligned} & \sim\{p \vee(q \rightarrow \sim r)\} \equiv \sim p \wedge \sim(q \rightarrow \sim r)[\because \sim(p \rightarrow q) \equiv p \wedge \sim q] \\ & \equiv \sim p \wedge(q \wedge \sim(\sim r)) \\ & \equiv \sim p \wedge(q \wedge r)\end{aligned}$
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