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The number of air molecules in a $(5 \mathrm{~m} \times 5 \mathrm{~m} \times 4 \mathrm{~m})$ room at standard temperature and pressure is of the order of
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Verified Answer
The correct answer is:
$3 \times 10^{27}$
$\mathrm{PV}=\mathrm{N} \times \mathrm{K} \times \mathrm{T}$
where $\mathrm{K}$ is Boltzmann constant
$\begin{array}{l}
10^{5} \times 100=\mathrm{N} \times 1.38 \times 10^{-23} \times 273 \\
\mathrm{~N} \approx 3 \times 10^{27}
\end{array}$
where $\mathrm{K}$ is Boltzmann constant
$\begin{array}{l}
10^{5} \times 100=\mathrm{N} \times 1.38 \times 10^{-23} \times 273 \\
\mathrm{~N} \approx 3 \times 10^{27}
\end{array}$
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