Search any question & find its solution
Question:
Answered & Verified by Expert
The number of protons, electrons and neutrons in a species are equal to 17,18 and 18 respectively. Which of the following will be the proper symbol of this species?
Options:
Solution:
2158 Upvotes
Verified Answer
The correct answer is:
\({ }_{17}^{35} \mathrm{Cl}^{-}\)
\(p=17, e=18, n=18\)
means, \(Z=17 \Rightarrow\) element is chlorine, which contains one electron more \((17+1)\), so it is chloride ion, \(\mathrm{Cl}^{-}\).
\(\Rightarrow\) Symbol: \({ }_{17}^{35} \mathrm{Cl}^{-}\);
Mass number, \(A=n+p=18+17=35\)
Atomic number, \(Z=17\)
means, \(Z=17 \Rightarrow\) element is chlorine, which contains one electron more \((17+1)\), so it is chloride ion, \(\mathrm{Cl}^{-}\).
\(\Rightarrow\) Symbol: \({ }_{17}^{35} \mathrm{Cl}^{-}\);
Mass number, \(A=n+p=18+17=35\)
Atomic number, \(Z=17\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.