Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
The number of solution of $\tan x+\sec x=2 \cos x$ in $[0,2 \pi)$ is
MathematicsTrigonometric EquationsJEE MainJEE Main 2002
Options:
  • A
    2
  • B
    3
  • C
    0
  • D
    1
Solution:
1461 Upvotes Verified Answer
The correct answer is:
3
The given equation is $\tan x+\sec x=2 \cos x \Rightarrow \sin x+1=2 \cos ^2 x$
$$
\begin{aligned}
& \Rightarrow \sin x+1=2\left(1-\sin ^2 x\right) \Rightarrow 2 \sin ^2 x+\sin x-1=0 \\
& \Rightarrow(2 \sin x-1)(\sin x+1)=0 \Rightarrow \sin x=\frac{1}{2},-1 \Rightarrow x=30^{\circ}, 150^{\circ}, 270^{\circ}
\end{aligned}
$$

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.