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The number of ways in which 9 persons can be divided into three equal groups
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The correct answer is:
$1680$
Total ways $=\frac{9!}{(3!)^3}=\frac{9 \times 8 \times 7 \times 6 \times 5 \times 4}{3 \times 2 \times 3 \times 2}=1680$.
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