Search any question & find its solution
Question:
Answered & Verified by Expert
The number of ways of arranging 8 boys and 8 girls in a row so that boys and girls sit alternately is
Options:
Solution:
2747 Upvotes
Verified Answer
The correct answer is:
$2 !(8 !)^2$
We have, 8 boys and 8 girls.
To tal number of arrangements of 8 boys and 8 girls.
Sit altemately is $8 ! \times 8 ! \times 2 !=2 !(8 !)^2$
To tal number of arrangements of 8 boys and 8 girls.
Sit altemately is $8 ! \times 8 ! \times 2 !=2 !(8 !)^2$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.