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The one which is least basic is
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The correct answer is:
$\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \mathrm{~N}$
Due to the presence of electron withdrawing group like Ph group decreases the electron density of nitrogen and hence, the lone pair of nitrogen are not available, for donation.
So, $\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \mathrm{~N}$ is least basic due to the presence of three electron withdrawing $\mathrm{Ph}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)$ groups.
So, $\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)_{3} \mathrm{~N}$ is least basic due to the presence of three electron withdrawing $\mathrm{Ph}\left(\mathrm{C}_{6} \mathrm{H}_{5}\right)$ groups.
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