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Question: Answered & Verified by Expert
The orbital angular momentum for an electron revolving in an orbit is given by $\sqrt{l(l+1)} \cdot \frac{\mathrm{h}}{2 \pi}$. This momentum for an s-electron will be given by
ChemistryStructure of AtomJEE MainJEE Main 2003
Options:
  • A
    zero
  • B
    $\frac{\mathrm{h}}{2 \pi}$
  • C
    $\sqrt{2} \cdot \frac{\mathrm{h}}{2 \pi}$
  • D
    $+\frac{1}{2} \cdot \frac{\mathrm{h}}{2 \pi}$
Solution:
2178 Upvotes Verified Answer
The correct answer is:
zero
For s-electron, $l=0 \quad \therefore$ angular momentum $=$ zero

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