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The order and degree of the differential equation $\sqrt{\frac{d y}{d x}}-4 \frac{d y}{d x}-7 x=0$ are respectively.
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The correct answer is:
1 and 2
$\begin{aligned} & \sqrt{\frac{d y}{d x}}-4 \frac{d y}{d x}-7 x=0 \\ & \therefore \sqrt{\frac{d y}{d x}}=4 \frac{d y}{d x}+7 x \text { and squaring both sides, we get } \\ & \frac{d y}{d x}=16\left(\frac{d y}{d x}\right)^2+56 x\left(\frac{d y}{d x}\right)+49 x^2 \\ & \therefore \text { Order }=1, \text { degree }=2\end{aligned}$
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