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The order and degree of the differential equation of parabolas having vertex at the origin and focus at $(a, 0)$ where a $>0$, are respectively
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Verified Answer
The correct answer is:
1,1
The eq. of parabolas having vertex at $(0,0) \&$ focus at $(a, 0)$, where $(a>0)$ is:
$$
\begin{array}{l}
y^{2}=4 a x \\
2 y \cdot \frac{d y}{d x}=4 a
\end{array}
$$
[on differentiating]
On putting the value of $(4 a)$ in eq. (1) we get,
$$
2 \mathrm{x} \cdot \frac{\mathrm{dy}}{\mathrm{dx}}-\mathrm{y}=0
$$
in order $=1 \&$ degree $=1$.
$$
\begin{array}{l}
y^{2}=4 a x \\
2 y \cdot \frac{d y}{d x}=4 a
\end{array}
$$
[on differentiating]
On putting the value of $(4 a)$ in eq. (1) we get,
$$
2 \mathrm{x} \cdot \frac{\mathrm{dy}}{\mathrm{dx}}-\mathrm{y}=0
$$
in order $=1 \&$ degree $=1$.
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