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The order of the reaction
$\mathrm{N}_{2} \mathrm{O}_{5} \rightarrow \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \mathrm{is}$
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$\mathrm{N}_{2} \mathrm{O}_{5} \rightarrow \mathrm{N}_{2} \mathrm{O}_{4}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \mathrm{is}$
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The correct answer is:
1
It is a first order reaction because rate of reaction $\propto\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]$
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