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The orthogonal trajectory of \( x^{2}-y^{2}=a^{2} \), where \( a \) is an arbitrary constant, is
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The correct answer is:
A hyperbola
x2 – y2 = a2
Product of slope of and slope of orthogonal trajectory of is
Slope of orthogonal trajectory of is
⇒ logx = – logy + logc
logxy = logc
⇒ xy = c
which is a rectangular hyperbola.
Product of slope of and slope of orthogonal trajectory of is
Slope of orthogonal trajectory of is
⇒ logx = – logy + logc
logxy = logc
⇒ xy = c
which is a rectangular hyperbola.
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