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The output $(X)$ of the logic circuit shown in figure will be

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Verified Answer
The correct answer is:
$X=A \cdot B$
$X=\overline{\overline{A B}}=A \cdot B$ (i.e., AND gate)
If the output $X$ of NAND gate is connected to the input of NOT gate (made from NAND gate by joining two inputs) from the given figure then we get back an AND gate.
If the output $X$ of NAND gate is connected to the input of NOT gate (made from NAND gate by joining two inputs) from the given figure then we get back an AND gate.
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