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The oxidation state of iron in $\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$ is,
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2
Oxidation state of iron $\left(x^{2}\right)$ in $\mathrm{K}_{4}\left[\mathrm{Fe}(\mathrm{CN})_{6}\right]$ is
$$
\begin{array}{r}
4+x+6 x(-1)=0 \\
x=2
\end{array}
$$
$$
\begin{array}{r}
4+x+6 x(-1)=0 \\
x=2
\end{array}
$$
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