The p H value of decinormal solution of N H 4 O H , which is 20 % ionized, is -

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Question: Answered & Verified by Expert

The

p H

value of decinormal solution of

{N H}_{4} O H

, which is

20 %

ionized, is -

ChemistryIonic EquilibriumNEET

Options:

A $13.30$
B $14.70$
C $12.30$
D $12.95$

Solution:

1777 Upvotes Verified Answer

The correct answer is:

12.30

[{OH}^{-}] = 0.1 \times \frac{20}{100}

[{O H}^{-}] = 0.1 \times 0.2 = 2 \times 10^{-2}

pOH= -log[OH^-] = 2- log2
pOH=1.7 , pH=14 – pOH = 14 - 1.7 = 12.3

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