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The parametric equations of the circle $x^2+y^2-6 x-2 y+9=0$ are
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Verified Answer
The correct answer is:
$x=3+\cos \theta, y=1+\sin \theta$
$\begin{aligned}
& x^2+y^2-6 x-2 y+9=0 \Rightarrow(x-3)^2+(y-1)^2=1^2 \Rightarrow x-3=\cos \theta \quad \text { and } \\
& y-1=\sin \theta
\end{aligned}$
Hence, parametric equation is $x=3+\cos \theta$ and $y=1+\sin \theta$
& x^2+y^2-6 x-2 y+9=0 \Rightarrow(x-3)^2+(y-1)^2=1^2 \Rightarrow x-3=\cos \theta \quad \text { and } \\
& y-1=\sin \theta
\end{aligned}$
Hence, parametric equation is $x=3+\cos \theta$ and $y=1+\sin \theta$
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