The percentage decrease in the weight of a rocket, when taken to a height of 32 km above the surface of earth will, be (Radius of earth = 6400 km )

Question

The percentage decrease in the weight of a rocket, when taken to a height of 32 km above the surface of earth will, be (Radius of earth = 6400 km ), 1 %, 3 %, 4 %, 0 . 5 %

MARKS App · Accepted Answer

Acceleration due to gravity at a height h R is g ' = g 1 - 2 h R Now, change in g is ∴ Δ g g = 2 h R Percentage change is ⇒ Δ g g × 100 = 2 h R × 100 = 2 × 32 6400 × 100 = 1 %

Search any question & find its solution

Looking for more such questions to practice?