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Question: Answered & Verified by Expert
The pH of 0.1M solution of acetic acid will be [degree of dissociation of acetic acid is 0.0132]
ChemistryIonic EquilibriumAP EAMCETAP EAMCET 2021 (20 Aug Shift 2)
Options:
  • A 4.32
  • B 3.14
  • C 1.14
  • D 2.88
Solution:
1446 Upvotes Verified Answer
The correct answer is: 2.88

Reaction:-

CH3COOHCH3COO- + H+c(0.1)                        0                   0c-                               

pH=-logH+

Degree of dissociation = α=0.0132

H+==0.1×0.0132=0.00132

pH=-logH+=-log0.00132=2.88

Hence, the pH of solution is 2.88.

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