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Question: Answered & Verified by Expert
The $\mathrm{pH}$ of $0.1 \mathrm{M}$ acetic acid solution is closest to [Dissociation constant of acid $\mathrm{K}_{\mathrm{a}}=1.8 \times 10^{-5}$ ]
ChemistryIonic EquilibriumKVPYKVPY 2017 (19 Nov SB/SX)
Options:
  • A $2.87$
  • B $1.00$
  • C $2.07$
  • D $4.76$
Solution:
2171 Upvotes Verified Answer
The correct answer is: $2.87$
$\left[\mathrm{H}^{+}\right]=\sqrt{\mathrm{K}_{\mathrm{a}} \cdot \mathrm{c}}=\sqrt{1.8 \times 10^{-5} \times 0.1}=\sqrt{1.8} \times 10^{-3}$
$\mathrm{pH}=3-\log (1.34)=2.87$

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