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The phase difference between the two particles situated on both the sides of a node is
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$180^{\circ}$
Both the sides of a node, two antinodes are present with separation $\frac{\lambda}{2}$
So phase difference between then
$\phi=\frac{2 \pi}{\lambda} \times \frac{\lambda}{2}=\pi$
So phase difference between then
$\phi=\frac{2 \pi}{\lambda} \times \frac{\lambda}{2}=\pi$
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