Search any question & find its solution
Question:
Answered & Verified by Expert
The $\mathrm{pK}_{\mathrm{a}}$ of oxoacids of chlorine in water follows the order
Options:
Solution:
1484 Upvotes
Verified Answer
The correct answer is:
$\mathrm{HClO}_{4} < \mathrm{HClO}_{3} < \mathrm{HClO}_{2} < \mathrm{HClO}$
Acidic strength of acid is
$$
\begin{array}{l}
\mathrm{HClO}_{4}>\mathrm{HClO}_{3}>\mathrm{HClO}_{2}>\mathrm{HClO} \\
{\left[\mathrm{H}^{+}\right] \uparrow \mathrm{ka} \uparrow \mathrm{p}^{\mathrm{ka}} \downarrow} \\
\therefore \mathrm{p}^{\mathrm{k}_{\mathrm{a}}} \text { order } \mathrm{HClO}_{4} < \mathrm{HClO}_{3} < \mathrm{HClO}_{2} < \mathrm{HClO}
\end{array}
$$
$$
\begin{array}{l}
\mathrm{HClO}_{4}>\mathrm{HClO}_{3}>\mathrm{HClO}_{2}>\mathrm{HClO} \\
{\left[\mathrm{H}^{+}\right] \uparrow \mathrm{ka} \uparrow \mathrm{p}^{\mathrm{ka}} \downarrow} \\
\therefore \mathrm{p}^{\mathrm{k}_{\mathrm{a}}} \text { order } \mathrm{HClO}_{4} < \mathrm{HClO}_{3} < \mathrm{HClO}_{2} < \mathrm{HClO}
\end{array}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.