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Question: Answered & Verified by Expert
The point of lines represented by $3 a x^2+5 x y+\left(a^2-2\right) y^2=0$ and perpendicular to each other for
MathematicsStraight LinesJEE MainJEE Main 2002
Options:
  • A
    two values of a
  • B
    $\forall a$
  • C
    for one value of a
  • D
    for no values of a
Solution:
2023 Upvotes Verified Answer
The correct answer is:
two values of a
$3 a+a^2-2=0 \Rightarrow a^2+3 a-2=0 \Rightarrow a=\frac{-3 \pm \sqrt{9+8}}{2}=\frac{-3 \pm \sqrt{17}}{2}$

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